skbio.tree.TreeNode.is_tip

TreeNode.is_tip()[source]

Returns True if the current node has no children.

State: Experimental as of 0.4.0.

Returns

True if the node is a tip

Return type

bool

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.is_tip())
False
>>> print(tree.find('a').is_tip())
True